Use the quadratic formula to find the exact solutions of 3x2 − 6x + 1 = 0. x equals negative b plus or minus the square root of the quantity b squared minus 4 times a times c all over 2 times a a 1 plus or minus 2 times the square root of 3 divided by 3 b negative 1 plus or minus 2 times the square root of 3 divided by 3 c 1 plus or minus the square root of 6 divided by 3 d negative 1 plus or minus the square root of 6 divided by 3
Use the quadratic formula to find the exact solutions of 3x2 − 6x + 1 = 0.
x equals negative b plus or minus the square root of the quantity b squared minus 4 times a times c all over 2 times a
a
1 plus or minus 2 times the square root of 3 divided by 3
b
negative 1 plus or minus 2 times the square root of 3 divided by 3
c
1 plus or minus the square root of 6 divided by 3
d
negative 1 plus or minus the square root of 6 divided by 3
Hello!
[tex]3x^{2} - 6x + 1 = 0\\\\x= \dfrac{-b \±\sqrt{b^{2}-4ac } }{2a} \\\\\\x = \dfrac{-(-6) \±\sqrt{(-6)^{2}-4*3*1 } }{2*3} \\\\\\x =\dfrac{6 \±\sqrt{24 } }{6}\\\\\boxed{x =\dfrac{3 \±\sqrt{6 } }{3}}[/tex]
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